9x^2-396x=0

Solution for 9x^2-396x=0 equation:

9x^2-396x=0

a = 9; b = -396; c = 0;
Δ = b2-4ac
Δ = -3962-4·9·0
Δ = 156816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{156816}=396$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-396)-396}{2*9}=\frac{0}{18}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-396)+396}{2*9}=\frac{792}{18}
=44
$